Optimal. Leaf size=92 \[ \frac{d \text{PolyLog}\left (2,-e^{a+b x}\right )}{2 b^2}-\frac{d \text{PolyLog}\left (2,e^{a+b x}\right )}{2 b^2}-\frac{d \text{csch}(a+b x)}{2 b^2}+\frac{(c+d x) \tanh ^{-1}\left (e^{a+b x}\right )}{b}-\frac{(c+d x) \coth (a+b x) \text{csch}(a+b x)}{2 b} \]
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Rubi [A] time = 0.0813309, antiderivative size = 92, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 4, integrand size = 14, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.286, Rules used = {4185, 4182, 2279, 2391} \[ \frac{d \text{PolyLog}\left (2,-e^{a+b x}\right )}{2 b^2}-\frac{d \text{PolyLog}\left (2,e^{a+b x}\right )}{2 b^2}-\frac{d \text{csch}(a+b x)}{2 b^2}+\frac{(c+d x) \tanh ^{-1}\left (e^{a+b x}\right )}{b}-\frac{(c+d x) \coth (a+b x) \text{csch}(a+b x)}{2 b} \]
Antiderivative was successfully verified.
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Rule 4185
Rule 4182
Rule 2279
Rule 2391
Rubi steps
\begin{align*} \int (c+d x) \text{csch}^3(a+b x) \, dx &=-\frac{d \text{csch}(a+b x)}{2 b^2}-\frac{(c+d x) \coth (a+b x) \text{csch}(a+b x)}{2 b}-\frac{1}{2} \int (c+d x) \text{csch}(a+b x) \, dx\\ &=\frac{(c+d x) \tanh ^{-1}\left (e^{a+b x}\right )}{b}-\frac{d \text{csch}(a+b x)}{2 b^2}-\frac{(c+d x) \coth (a+b x) \text{csch}(a+b x)}{2 b}+\frac{d \int \log \left (1-e^{a+b x}\right ) \, dx}{2 b}-\frac{d \int \log \left (1+e^{a+b x}\right ) \, dx}{2 b}\\ &=\frac{(c+d x) \tanh ^{-1}\left (e^{a+b x}\right )}{b}-\frac{d \text{csch}(a+b x)}{2 b^2}-\frac{(c+d x) \coth (a+b x) \text{csch}(a+b x)}{2 b}+\frac{d \operatorname{Subst}\left (\int \frac{\log (1-x)}{x} \, dx,x,e^{a+b x}\right )}{2 b^2}-\frac{d \operatorname{Subst}\left (\int \frac{\log (1+x)}{x} \, dx,x,e^{a+b x}\right )}{2 b^2}\\ &=\frac{(c+d x) \tanh ^{-1}\left (e^{a+b x}\right )}{b}-\frac{d \text{csch}(a+b x)}{2 b^2}-\frac{(c+d x) \coth (a+b x) \text{csch}(a+b x)}{2 b}+\frac{d \text{Li}_2\left (-e^{a+b x}\right )}{2 b^2}-\frac{d \text{Li}_2\left (e^{a+b x}\right )}{2 b^2}\\ \end{align*}
Mathematica [C] time = 2.67384, size = 313, normalized size = 3.4 \[ -\frac{d \left (-a \log \left (\tanh \left (\frac{1}{2} (a+b x)\right )\right )-i \left (i \left (\text{PolyLog}\left (2,-e^{i (i a+i b x)}\right )-\text{PolyLog}\left (2,e^{i (i a+i b x)}\right )\right )+(i a+i b x) \left (\log \left (1-e^{i (i a+i b x)}\right )-\log \left (1+e^{i (i a+i b x)}\right )\right )\right )\right )}{2 b^2}+\frac{d \text{csch}\left (\frac{a}{2}\right ) \sinh \left (\frac{b x}{2}\right ) \text{csch}\left (\frac{a}{2}+\frac{b x}{2}\right )}{4 b^2}+\frac{d \text{sech}\left (\frac{a}{2}\right ) \sinh \left (\frac{b x}{2}\right ) \text{sech}\left (\frac{a}{2}+\frac{b x}{2}\right )}{4 b^2}-\frac{c \text{csch}^2\left (\frac{1}{2} (a+b x)\right )}{8 b}-\frac{c \text{sech}^2\left (\frac{1}{2} (a+b x)\right )}{8 b}-\frac{c \log \left (\tanh \left (\frac{1}{2} (a+b x)\right )\right )}{2 b}-\frac{d x \text{csch}^2\left (\frac{a}{2}+\frac{b x}{2}\right )}{8 b}-\frac{d x \text{sech}^2\left (\frac{a}{2}+\frac{b x}{2}\right )}{8 b} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.033, size = 197, normalized size = 2.1 \begin{align*} -{\frac{{{\rm e}^{bx+a}} \left ( bdx{{\rm e}^{2\,bx+2\,a}}+bc{{\rm e}^{2\,bx+2\,a}}+bdx+d{{\rm e}^{2\,bx+2\,a}}+cb-d \right ) }{{b}^{2} \left ({{\rm e}^{2\,bx+2\,a}}-1 \right ) ^{2}}}+{\frac{c{\it Artanh} \left ({{\rm e}^{bx+a}} \right ) }{b}}+{\frac{d\ln \left ( 1+{{\rm e}^{bx+a}} \right ) x}{2\,b}}+{\frac{d\ln \left ( 1+{{\rm e}^{bx+a}} \right ) a}{2\,{b}^{2}}}+{\frac{d{\it polylog} \left ( 2,-{{\rm e}^{bx+a}} \right ) }{2\,{b}^{2}}}-{\frac{d\ln \left ( 1-{{\rm e}^{bx+a}} \right ) x}{2\,b}}-{\frac{d\ln \left ( 1-{{\rm e}^{bx+a}} \right ) a}{2\,{b}^{2}}}-{\frac{d{\it polylog} \left ( 2,{{\rm e}^{bx+a}} \right ) }{2\,{b}^{2}}}-{\frac{da{\it Artanh} \left ({{\rm e}^{bx+a}} \right ) }{{b}^{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} -d{\left (\frac{{\left (b x e^{\left (3 \, a\right )} + e^{\left (3 \, a\right )}\right )} e^{\left (3 \, b x\right )} +{\left (b x e^{a} - e^{a}\right )} e^{\left (b x\right )}}{b^{2} e^{\left (4 \, b x + 4 \, a\right )} - 2 \, b^{2} e^{\left (2 \, b x + 2 \, a\right )} + b^{2}} + 8 \, \int \frac{x}{16 \,{\left (e^{\left (b x + a\right )} + 1\right )}}\,{d x} + 8 \, \int \frac{x}{16 \,{\left (e^{\left (b x + a\right )} - 1\right )}}\,{d x}\right )} + \frac{1}{2} \, c{\left (\frac{\log \left (e^{\left (-b x - a\right )} + 1\right )}{b} - \frac{\log \left (e^{\left (-b x - a\right )} - 1\right )}{b} + \frac{2 \,{\left (e^{\left (-b x - a\right )} + e^{\left (-3 \, b x - 3 \, a\right )}\right )}}{b{\left (2 \, e^{\left (-2 \, b x - 2 \, a\right )} - e^{\left (-4 \, b x - 4 \, a\right )} - 1\right )}}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.83789, size = 2677, normalized size = 29.1 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (c + d x\right ) \operatorname{csch}^{3}{\left (a + b x \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (d x + c\right )} \operatorname{csch}\left (b x + a\right )^{3}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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